解决Jquery下拉框数据动态获取的问题

网络编程 2024/11/13 佚名

3 2 1

废话不多说，直接上源码：

select.jsp

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
 <head>
 <base href="<%=basePath%>" rel="external nofollow" >
 
 <title>My JSP 'select.jsp' starting page</title>
 
	<meta http-equiv="pragma" content="no-cache">
	<meta http-equiv="cache-control" content="no-cache">
	<meta http-equiv="expires" content="0"> 
	<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
	<meta http-equiv="description" content="This is my page">
	<!--
	<link rel="stylesheet" type="text/css" href="styles.css" rel="external nofollow" >
	-->
	<script type="text/javascript" src="/UploadFiles/2021-04-02/jquery-2.1.1.min.js">

struts.xml


<"1.0" encoding="UTF-8" "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>
	<constant name="struts.i18n.encoding" value="UTF-8"></constant>
	<package name="simpleton" extends="struts-default,json-default">
	
		<action name="*JsonAction" method="{1}"
				class="jquery.chisj.action.JsonAction">
			<result name="fail">error.jsp</result>
			<result type="json">
				<param name="root">result</param>
			</result>
		
		</action>
		
		<action name="AppTypeShow"
				class="jquery.chisj.action.NtAppAction"
				method="appTypeShow">
			<result name="fail">error.jsp</result>
			<result type="json">
				<param name="root">result</param>
			</result>
		</action>
		
		<action name="AppClassShow"
				class="jquery.chisj.action.NtAppAction"
				method="appClassShow">
			<result name="fail">error.jsp</result>
			<result type="json">
				<param name="root">result</param>
			</result>		
		</action>
		
	</package>
</struts> 



NtAppAction.java


/**
 * 
 */
package jquery.chisj.action;
import java.util.ArrayList;
import java.util.List;
import jquery.chisj.entity.APPClass;
import jquery.chisj.entity.APPType;
import com.opensymphony.xwork2.ActionSupport;
import net.sf.json.JSONArray;
/**
 * @ClassName: NtAppAction
 * @Description: TODO
 * @Author: chisj chisj@foxmail.com
 * @Date 2016年1月20日 下午4:53:50
 *
 */
public class NtAppAction extends ActionSupport {
	private String result;
	
	public String appTypeShow() {
		System.out.println("---app type show---");
		List<APPType> appTypeList = new ArrayList<APPType>();
		try {
			APPType appType_1 = new APPType();
			APPType appType_2 = new APPType();
			appType_1.setId(Short.valueOf("1"));
			appType_1.setName("Android");
			appType_2.setId(Short.valueOf("2"));
			appType_2.setName("iOS");
			appTypeList.add(appType_1);
			appTypeList.add(appType_2);
			JSONArray jsonArray = JSONArray.fromObject(appTypeList);
			result = String.valueOf(jsonArray);
		} catch (Exception e) {
			e.printStackTrace();
		}
		
		return SUCCESS;
	}
	
	public String appClassShow() {
		System.out.println("---app class show---");
		List<APPClass> appClassList = new ArrayList<APPClass>();
		try {
			APPClass appClass_1 = new APPClass();
			APPClass appClass_2 = new APPClass();
			appClass_1.setId(Short.valueOf("1"));
			appClass_1.setName("种类1");
			appClass_2.setId(Short.valueOf("2"));
			appClass_2.setName("种类2");
			appClassList.add(appClass_1);
			appClassList.add(appClass_2);
			JSONArray jsonArray = JSONArray.fromObject(appClassList);
			result = String.valueOf(jsonArray);
		} catch (Exception e) {
			e.printStackTrace();
		}
		
		return SUCCESS;
	}
	
	public String getResult() {
		return result;
	}
	
	public void setResult(String result) {
		this.result = result;
	}
	
}



以上这篇解决Jquery下拉框数据动态获取的问题就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持。

Jquery,下拉框,数据,动态获取