给Python的Django框架下搭建的BLOG添加RSS功能的教程

脚本专栏 2024/12/27 佚名

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前些天有位网友建议我在博客中添加RSS订阅功能，觉得挺好，所以自己抽空看了一下如何在Django中添加RSS功能，发现使用Django中的syndication feed framework很容易实现。

具体实现步骤和代码如下：

1、Feed类

# -*- coding: utf-8 -*-
from django.conf import settings
from django.contrib.syndication.views import Feed
from django.utils.feedgenerator import Rss201rev2Feed
 
from blog.models import Article
from .constants import SYNC_STATUS
 
 
class ExtendedRSSFeed(Rss201rev2Feed):
 mime_type = 'application/xml'
 """
 Create a type of RSS feed that has content:encoded elements.
 """
 def root_attributes(self):
  attrs = super(ExtendedRSSFeed, self).root_attributes()
  attrs['xmlns:content'] = 'http://purl.org/rss/1.0/modules/content/'
  return attrs
 
 def add_item_elements(self, handler, item):
  super(ExtendedRSSFeed, self).add_item_elements(handler, item)
  handler.addQuickElement(u'content:encoded', item['content_encoded'])
 
 
class LatestArticleFeed(Feed):
 feed_type = ExtendedRSSFeed
 
 title = settings.WEBSITE_NAME
 link = settings.WEBSITE_URL
 author = settings.WEBSITE_NAME
 description = settings.WEBSITE_DESC + u"关注python、django、vim、linux、web开发和互联网"
 
 def items(self):
  return Article.objects.filter(hided=False, published=True, sync_status=SYNC_STATUS.SYNCED).order_by('-publish_date')[:10]
 
 def item_extra_kwargs(self, item):
  return {'content_encoded': self.item_content_encoded(item)}
 
 def item_title(self, item):
  return item.title
 
 # item_link is only needed if NewsItem has no get_absolute_url method.
 def item_link(self, item):
  return '/article/%s/' % item.slug
 
 def item_description(self, item):
  return item.description
 
 def item_author_name(self, item):
  return item.creator.get_full_name()
 
 def item_pubdate(self, item):
  return item.publish_date
 
 def item_content_encoded(self, item):
  return item.content

2、URL配置

from django import VERSION
 
if VERSION[0: 2] > (1, 3):
 from django.conf.urls import patterns, include, url
else:
 from django.conf.urls.defaults import patterns, include, url
from .feeds import LatestArticleFeed
 
 
urlpatterns = patterns(
 '',
 url(r'^feed/$', LatestArticleFeed()),
)

Python,Django